Re: [xsl] Transform XML

[me@xxxxxxxxxxxx]

> Hello, I need to take the following XML and transform
> it into something
> quite simpler, this might be the result:
> 
> <?xml version="1.0">
> <FLDS>
>     <FLD name="orig_fld_name"/>
>     <FLD name="orig_fld_name"/>
>     <FLD name="orig_fld_name"/>
>     <FLD name="orig_fld_name"/>
>     ...
> </FLDS>
> 
> Now, I get how to loop through the following XML, and
> all that jazz... but I
> need help setting up the template so that I can write
> back XML.  As in:  how
> do you write XML tags (nodes), can you prefix them?  I
> have set the XSL
> output to "XML", is there some sort of copy command.
> Thanks!
> Karl
> 
> What I have to work with is a persisted ADOXML
> Recordset, and it looks like
> this:

Go ahead and send 20% of you paycheck to Rob Rohan...
hehehehe

<?xml version="1.0" encoding="utf-8"?>
<!--
	Author: 
	File: 
	Date: 
	Purpose: 
-->
<xsl:stylesheet version="1.0" 
	xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
	xmlns:s="uuid:BDC6E3F0 6DA3 11d1 A2A3 00AA00C14882"
	exclude-result-prefixes="s xsl"
>
	<xsl:output method="xml" indent="yes"
encoding="UTF-8"/>

	<xsl:template match="/">
	<FLDS>
		<xsl:apply-templates />
	</FLDS>
	</xsl:template>
	
	<xsl:template
match="/xml/s:Schema/s:ElementType/s:AttributeType">
	<xsl:element name="FLD">
		<xsl:attribute name="name">
			<xsl:value-of select="@name" />
		</xsl:attribute>
	</xsl:element>
	</xsl:template>
</xsl:stylesheet>

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