RE: [xsl] how to get rid of tag names

Sundar,
Sorry,I put abridged version of my source file in my question. The diff is
that I have multiple tags under BODY node, I need all of them for every <h>
node until the next <h> node:
<html>
  <body>
    <h>header1</h>
    <p>p line</p>
    <d>d line</d>

    <h>header2</h>
    <a>a line</a>
    <b>b line</b>
    ...
  </body>
</html>
Thus my xsl with following-sibling expression.
With Sundar's version I will only have the first sibling after <h> for every
<h> node.
I found this template on XSL-list that gives nodes between two nodes with
the same name (200008/msg01102) 

<xsl:template match="tag"
<group>
   <xsl:copy-of select="
       following-sibling::*[generate-id(following-sibling::tag[1])=
	generate-id(current()/following-sibling::tag[1])]"/>
</group>
</xsl:template>

But I don't know how to put it to work the right way. My xsl

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="html/body/h">
<ROWSET>
  <xsl:for-each select=".">
   <ROW>
     <HEADER>
       <xsl:value-of select="."/>
     </HEADER>
     <BODY>
       <xsl:value-of select="
 
following-sibling::*[generate-id(following-sibling::html/body/h[1])=
	   generate-id(current()/following-sibling::html/body/h[1])]"/>
     </BODY>
   </ROW>
  </xsl:for-each> 
</ROWSET>
</xsl:template> 
</xsl:stylesheet> 

gives me the output 

<?xml version = '1.0'?>
<ROWSET>
  <ROW>
   <HEADER>header1</HEADER>
   <BODY>p line</BODY>
  </ROW>
</ROWSET>
p line
d line
<ROWSET>
  <ROW>
   <HEADER>header2</HEADER>
   <BODY>a line</BODY>
  </ROW>
</ROWSET>
a line
b line

instead of what I want:

<?xml version = '1.0'?>
<ROWSET>
 <ROW>
  <HEADER>header1</HEADER>
  <BODY>
    p line
    d line
  </BODY>
 </ROW>
 <ROW>
  <HEADER>header2</HEADER>
  <BODY>
    a line
    b line
  </BODY>
 </ROW>
</ROWSET>    

Thank you.
Anatoliy Smirnov
Oracle Mid-Atlantic Consulting


-----Original Message-----
From: Sundar Shanmugasundaram [mailto:SSHANMUGASUNDARAM@xxxxxxxxxxxxx]
Sent: Thursday, May 01, 2003 11:05 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] how to get rid of tag names


USe this xsl

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<ROWSET>
<xsl:for-each select="html/body/h">
<ROW>
   <HEADER>
     <xsl:value-of select="."/>
   </HEADER>
   <BODY>
   <xsl:value-of select="
       following-sibling::*[generate-id(following-sibling::html/body/h[1])=
	generate-id(current()/following-sibling::html/body/h[1])]"/>
   </BODY>
 </ROW>
</xsl:for-each>
</ROWSET>
</xsl:template> 
</xsl:stylesheet>

sundar

-----Original Message-----
From: Smirnov, Anatoliy [mailto:anatoliy.smirnov@xxxxxxxxxxx]
Sent: Thursday, May 01, 2003 8:32 PM
To: 'XSL-List@xxxxxxxxxxxxxxxxxxxxxx'
Subject: [xsl] how to get rid of tag names


Hello,
Sorry for such a dumb question but I am new here.

I need to get rid of tag names <p> and </p> in the result document.

<?xml version = '1.0'?>
<ROWSET>
  <ROW>
    <HEADER>
	header
    </HEADER>
    <BODY>
       <p>p line</p>
    </BODY>
  </ROW>
</ROWSET>

so instead of
       <p>p line</p>
I just need to have
       p line

I am getting this from this source

<html>
  <body>
    <h>header</h>
    <p>p line</p>
  </body>
</html>

running this xsl

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<ROWSET>
<xsl:for-each select="html/body/h">
<ROW>
   <HEADER>
     <xsl:value-of select="."/>
   </HEADER>
   <BODY>
   <xsl:copy-of select="
       following-sibling::*[generate-id(following-sibling::html/body/h[1])=
	generate-id(current()/following-sibling::html/body/h[1])]"/>
   </BODY>
 </ROW>
</xsl:for-each>
</ROWSET>
</xsl:template> 
</xsl:stylesheet>

Thank you.
Anatoliy Smirnov

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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