Subject: Re: [xsl] What is the best way to cast integer to string in XSLT2? From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Sun, 11 May 2003 14:41:33 +0100 |
Hi Dimitre, > With Saxon 7.5 I'm getting an error on the following: > > <xsl:value-of select="concat(position(), '. ', ., '
')"/> > > "Type error in first argument of call to concat(): > Required type is xs:string; supplied value has type xs:integer" > > 1. Why doesn't the XSLT processor perform an implicit cast from > integer to string? This is quite natural, as any atomic type has a > string representation and can be converted to string. This is a good example of what I meant during my talk at XML Europe about life getting harder for XSLT users because of the strong typing in XPath 2.0. XPath 2.0 allows implicit casting: 1. from xdt:untypedAtomic (the type of untyped nodes) to any atomic type 2. from any atomic type to its base type (up the atomic type hierarchy) 3. from xs:decimal (and its subtypes) to xs:float or xs:double and from xs:float to xs:double As you say, it is possible to cast values of most types into a string (exceptions are xs:QName and xs:NOTATION), but in terms of the type hierarchy used by XPath 2.0, it is not the case that every type is derived from xs:string. (I guess you're aware of the recent XML-Dev discussion on this topic.) So you have to perform the casting explicitly. > 2. My current solution is to use > > string(position()) > > Is this the best/recommended solution? Yes. For atomic values like the integer returned by position(), it returns the same as xs:string(position()); the latter is just longer and requires an extra namespace declaration. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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