[xsl] table column

["Fei Zheng" <Fei.Zheng@xxxxxxx>]

I'd like to have a two column table to look like

item1 		item2
item3		item4	
item5		item6


but the output from the following code always gives an empty cell like

item1		
		item2
item3	
		item4
item5
		item6
	

<xsl:template match="item">
	<xsl:variable name="current-node" select="position()"/>
	<table>
	<tr>
		<td>
		     <xsl:for-each select=".">
			<xsl:if test="($current-node mod 2 &gt; 0) ">
				<xsl:apply-templates select="content"/>
			</xsl:if>
		     </xsl:for-each>
		</td>
		<td>
		     <xsl:for-each select=".">
			<xsl:if test="($current-node mod 2 = 0) ">
				<xsl:apply-templates select="content"/>
			</xsl:if>
		     </xsl:for-each>
		</td>
	</tr>
	</table>
</xsl:template>

Is there a way to get the correct column layout? Thanks!




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