Subject: RE: [xsl] Pass node to template From: David Neary <David@xxxxxxxxx> Date: Tue, 20 May 2003 17:50:49 +0200 |
De : Karl J. Stubsjoen [mailto:karl@xxxxxxxxxxxxx] > Hello, Hi. > <xsl:variable name="EDITPROP" select="EDITPROPS"/> Here the variable EDITPROP is a reference to the nodeset matching the XPath expression in the select (EDITPROPS). > <xsl:call-template name="MAKE_INPUT_BOX"> > <xsl:with-param name="nodEdit"><xsl:value-of > select="$EDITPROP" /></xsl:with-param> Here nodEdit is not a nodeset, but a tree fragment. That is, the parameter is the bit of a tree between the end of the <xsl:variable> and the start of the </xsl:variable> > </xsl:call-template> > > Here is the beginning part of my template that fails: > <xsl:template name="MAKE_INPUT_BOX"> > <xsl:value-of select="$nodEdit/@type"/> You can't do tree operations on a result fragment. What you want is to actually pass the nodeset into the template. To do that, change the with-param to <xsl:with-param name="nodEdit" select="$EDITPROP" /> Now, the parameter type in the template is the type of the expression "$EDITPROP", which presumably is a nodeset. Cheers, Dave. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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