Subject: RE: [xsl] sorting question From: "Americo Albuquerque" <aalbuquerque@xxxxxxxxxxxxxxxx> Date: Wed, 28 May 2003 18:08:35 +0100 |
Hi > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Lars Huttar > Sent: Tuesday, May 27, 2003 9:17 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] sorting question > > > > I want to process all 'sd:Service' nodes that have > > sd:ServiceDescription/@ServiceName='Y', > > except the one with min 'sd:ServiceID'. > > > > What is the condition returning the node-set I want ? > > (I have done it by " xsl:sort + xsl:if test='position() > > 1'> ", but > > I would like more elegant solution -> only one xsl:for-each) > > I don't know of any way more elegant. > > Maybe you're thinking of something that uses simply a select > expression without any xsl:sort or xsl:if, e.g. > > select="/*/sd:Service[sd:ServiceDescription/@ServiceName='Y' > and ../sd:Service[sd:ServiceID < current()/sd:ServiceID]]" > select="sd:Service[sd:ServiceDescription/@ServiceName='Y' and sd:ServiceID > ../sd:Service/sd:ServiceID]" will work too if the current node is sd:Services. It is similar to yours but with just one predicate. (...) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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