Subject: [xsl] passing node-set through multiple templates From: silvan <silvan@xxxxxxxxx> Date: Fri, 30 May 2003 16:12:10 +0200 |
Hi, Im having the following situation; - A template which calls template 'Display' with a node-set as parameter ... <xsl:template match="/"> <xsl:call-template name="Display"> <xsl:with-param name="rows" select="//path/to/nodes"/> </xsl:call-template> </xsl:template> ... template Diplay kindly gets $rows, does some further magic and is supposed to call template 'Display_ext' with again $rows and an additional value ... <xsl:template name="Display"> <xsl:param name="rows"/> <xsl:variable name="item" select="some_value"/> <xsl:if test="$rows"> <xsl:call-template name="Display_ext"> <xsl:with-param name="rows" select="$rows"/> <xsl:with-param name="item" select="$item"/> </xsl:call-template> </xsl:if> </xsl:template> ... now, strangely, Display_ext is not able to assign $rows[$item], even though $rows is unchanged ... <xsl:template name="Display_ext"> <xsl:param name="rows"/> <xsl:param name="item"/> <xsl:value-of select="$rows[$item]"/> </xsl:template> ... the errormessage is as follows; XPath error Invalid type in $images[1] .. Does anyone has an idea on what could be the failure's reason or on how one can pass a node-set as variable through multiple templates? I appologize if this question falls into the newbie-section ... silvan -- XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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