RE: [xsl] Re: Flat -> Hierarchy --- Continue

[Dongling Ding <dling61@xxxxxxxxx>]

Lars,

I works fine except for the following line:


<xsl:variable name="next-is-child" select=
     "//hierarchy/node[parent = Label and child =
$next/Label]" />

The expression "parent = Label and child =
$next/Label" doesn't work. I have to assign them to
variables first:

 xsl:variable name="valueOfParent" select="Label"/>
 <xsl:variable name="valueOfChild"
select="$next/Label"/>


Is this XPath's problem?


Thanks a lot


Dongling





--- Lars Huttar <lars_huttar@xxxxxxx> wrote:
> Dongling Ding wrote:
> > Hi Lars,
> > 
> > I tried to use the recursive way to generate
> hierarchy
> > structure. The example I have is to generate
> hierarchy
> > by recursively call template itself without
> looking at
> > if it's sibling or child. So the structure would
> be:
> > 
> > <A>
> >    <B>
> >       <C/>
> >     </B>
> > </A>
> > 
> > However, my case is when I get a node I have to
> look
> > at another table(the list of nodes containing
> parent
> > and child elements) to see if this node is sibling
> or
> > child.
> > 
> > 
> > <xsl:template match="/doc">
> > 
> >  <xsl:call-template name="level">
> >   <xsl:with-param name="node"
> select="/doc/Node[1]"/>
> >  </xsl:call-template>
> > 
> > </xsl:template>
> > 
> > 
> > <xsl:template name="level">
> >         <xsl:param name="node"/>
> > 
> >  <xsl:variable name="n"
> > select="normalize-space($node)"/>
> >  <xsl:element name="{$n}">
> > 
> >   <xsl:if test="$node/following::Node">
> >  ***** Here I have to look at another set of
> >  **** elements   
> > ****   to decide if the current node is seiling or
> ***
> >   child. If it is seiling, not call the template.
> > 
> >    <xsl:call-template name="level">
> >    <xsl:with-param name="node"
> > select="$node/following::Node"/>
> >    </xsl:call-template>
> > 
> >   </xsl:if>
> > 
> >  </xsl:element>
> > 
> > </xsl:template>
> > 
> > 
> > So, how can I look at another set of elments. Or
> just
> > like call a function with two parameters and
> return
> > value is boolean in XSLT?
> 
> Sure, you could do that... in XSLT 1.0, you'd have
> to
> call a template, and the value wouldn't be boolean
> as
> such, but it could be a string that evaluates to
> true()
> or false() in a boolean context (depending on
> whether its length
> is positive or zero).
> 
> But it would probably be simpler to use an inline
> XPath test,
> as follows, than to call the above template with
> parameters.
> 
> Anyway, here would be my solution, assuming your
> input XML
> document is something like
> <doc>
>   <Members>
>     <Member>...</Member>
>     ...
>   </Members>
>   <hierarchy>
>     ...
>   </hierarchy>
> </doc>
>   
> 
> <xsl:template match="/doc">
>   <xsl:apply-templates
> select="/doc/Members/Member[1]"/>
> </xsl:template>
> 
> <xsl:template match="Member">
> 
>   <xsl:variable name="next"
> select="following-sibling::Member[1]" />
>   <xsl:variable name="next-is-child" select=
>      "//hierarchy/node[parent = Label and child =
> $next/Label]" />
> 
>   <xsl:variable name="n"
> select="normalize-space(Label)"/>
> 
>   <xsl:element name="{$n}">
>     <!-- If next Member is child of current Member,
> process it inside
>       this result element. -->
>     <xsl:if test="$next-is-child">
>       <xsl:apply-templates select="$next" />
>     </xsl:if>
>   </xsl:element>
> 
>   <!-- If next Member is not child of current
> Member, process it outside
>      the above result element. -->
>   <xsl:if test="not($next-is-child)">
>     <xsl:apply-templates select="$next" />
>   </xsl:if>
> </xsl:template>
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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