Subject: RE: [xsl] using variables correctly From: "Michael Kay" <mhk@xxxxxxxxx> Date: Mon, 2 Jun 2003 16:31:53 +0100 |
You are very confused. Variables represent values, they do not represent bits of XPath expressions. They are not macros. In the expression [../@owner=3] you can replace 3 by a variable reference, because it is a value. You can also replace ../@owner by a variable reference, so long as the value of the variable is the node-set selected by the expression ../@owner - you can't replace it by a variable whose value is the string "../@owner". Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Krueger, Philipp > Sent: 02 June 2003 14:41 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx; > xsl-list-digest@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] using variables correctly > > > i try to write a dynamical database using xsl-processing and > somehow i can't get the variables to work correctly: > > <xsl:if test="$search != ''"> > <xsl:for-each select="database/computer[@owner = $searchparam]"> > > the if works, the for works as well, but only if i use > "@owner" - if i write the following line "<xsl:for-each > select="database/computer[$search = $searchparam]">" ($search > is "@owner") the output stays empty... now i > wonder: why does comparing to a variable work with "xsl:if" > but not with "xsl:for-each"? i also tried setting the whole > content of the "select"-statement as a variable but that > neither worked ($search was "database/computer[@owner = > $searchparam]"). i also tried to set $search to $search = > "$searchparam" and use that as in "<xsl:for-each > select="database/computer[$search]">"but that neither worked. > i am desperate > - can anybody help, please? > > greetings, > > philipp > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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