RE: [xsl] OR statement

Subject: RE: [xsl] OR statement
From: "Lars Huttar" <lars_huttar@xxxxxxx>
Date: Tue, 3 Jun 2003 10:58:09 -0500
> I'm transforming two (or more) RSS docs into one master xml 
> that I'll be
> using to display on our portal. I'm running into an issue 
> where one of the
> rss docs uses a date element called <dc:date> and another 
> uses <pubdate>.
> I'd like to transform them so that the final xml document uses only
> <pubdate>. 
> I've tried a couple of approaches:
> <xsl:if test="(name() = pubdate or dc:date)">

There are a few problems with this...

1) The "or" operator is meant to connect two boolean expressions,
   so instead of
      name() = pubdate or dc:date
   you want
      name() = pubdate or name() = dc:date

2) pubdate needs to be quoted; otherwise it is interpreted as
   "the string value of the child element of . whose name is 'pubdate'"
   so you want
      name() = 'pubdate' or name() = 'dc:date'
      self::pubdate or self::dc:date

   The latter form has the benefit of doing proper namespace checking.
   (Assuming you've declared the dc namespace in your stylesheet.)

> Anyone know how I can easily check if it's the <dc:date> or 
> the <pubdate>
> and tranform it to a <pubdate> if it's the <dc:date> (while inside a
> <xsl:for-each>)?

You were on the right track...

<xsl:if test="self::pubdate or self::dc:date">
  <xsl:element name="pubdate">
    <xsl:value-of select="." />


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