Subject: [xsl] Extracting link information from xml document and displaying it in browser as hyperlink From: bmcleere@xxxxxxxxxx Date: Tue, 10 Jun 2003 11:27:56 +0100 |
Hi, I have an xml document with a <location> tag amongst others e.g. <location> http://someserver.ie</location>. I want to retrieve the URL information and display it as a hyperlink in the browser. Currently, I can view the URL information but it is not a hyperlink. I thought of using the following:- <xsl:template match="technical/location"> <a href="http://{@link}"><xsl:value-of select="."/></a> </xsl:template> I will be searching different documents so hardwiring in the URL where it says "@link" would not provide a solution for me. I think that if I could declare a variable in xsl to store the retrieved data and then get at the contents of this variable within the <a href...> tag - this would provide a solution. How to do it is another question:-) Any help with this matter would be very much appreciated. Kindest regards, Brenda Cleere XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] saxon sql extensions in xslt, Jim Fuller | Thread | Re: [xsl] Extracting link informati, David Carlisle |
Re: [xsl] Namespaces, David Totten | Date | Re: [xsl] xslt 2, David Carlisle |
Month |