RE: [xsl] Extracting link information from xml document and displaying it in browser as hyperlink

[Jarno.Elovirta@xxxxxxxxx]

Hi,

>  <location> http://someserver.ie</location>. 
>  
>  I want to retrieve the URL information and display it as a 
>  hyperlink in the browser.
>  
>  Currently, I can view the URL information but it is not a hyperlink. 
>  
>  I thought of using the following:-
>  <xsl:template match="technical/location">
>  <a href="http://{@link}";><xsl:value-of select="."/></a>
>  </xsl:template>
>  
>  I will be searching different documents so hardwiring in the 
>  URL where it says "@link" would not provide a solution for 
>  me. I think that if I could declare a variable in xsl to 
>  store the retrieved data and then get at the contents of this 
>  variable within the <a href...> tag - this would provide a solution.

  <a href="{.}">
    <xsl:value-of select="."/>
  </a>

if the source is as you showed above. If the location of the URL varies, try something like

  <a>
    <xsl:attribute name="href">
      <xsl:choose>
        <xsl:when test="...">
          ...
        </xsl:when>
        ...
      </xsl:choose>
    </xsl:attribute>
    <xsl:value-of select="."/>
  </a>

Cheers,

Jarno - Front Line Assembly: Virus (Counterized Mix)

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