[xsl] node() implementation

[Jarkko.Moilanen@xxxxxx]

I was given this question: 
"I have a difficulty to find  an example of  stylesheet which strips all xml
tags leaving only text and attributes ( I need it for indexing ) .
It should work with IE.  Some examples I picked up from Internet just upset IE." 

So what I suggested was:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:output method="text"/>

<xsl:template match="node()">
node:<xsl:apply-templates/>
<xsl:apply-templates select="@*"/>
</xsl:template>

<xsl:template match="@*">
attr:<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>

For some reason with MSXML it did not work (produced not values of 
node values or attributes. It did work with Xalan C++.

The following stylesheet is according to a third party working 
correctly.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="text"/>

<xsl:template match="*">
        node:<xsl:apply-templates select="node()"/>
        <xsl:apply-templates select="@*"/>
</xsl:template>

<xsl:template match="@*">
        attr:<xsl:value-of select="."/>
</xsl:template>

</xsl:stylesheet>


So my question is which processor (well IE aint a processor)
is doing the job correct 

Cheers,
</Jarkko>

***************************************************
* Jarkko Moilanen                                 *
* Project Researcher, ITCM (www.itcm.org)         *
* Profound XML technology Expert                  *
* University of Tampere                           *
* Hypermedia Laboratory                           *
***************************************************

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