Re: [xsl] Current node position

["Corey Wilson" <corey@xxxxxxxxxxxxxxxxxxxxxx>]

you could try putting the date in a variable

<variable name="dateList" select="./date" />
then do the position and count of $dateList

----- Original Message ----- 
From: "jwhitney" <jwhitney@xxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, June 11, 2003 14:55
Subject: [xsl] Current node position


> Hello,
>
> I'm trying to generate html code for "Date 1 of 2", "Date 2 of 2", etc.,
from
> XML as below:
>
> <a>
>    <b/>
>    <c/>
>    <date>text</date>
>    <date>text again</date>
> </a>
>
> from within a template that matches "d".  The following stylesheet
fragment:
>
> <xsl:template match="d">
>   <xsl:value-of select="position()" />
>   <xsl:text> of </xsl:text>
>   <xsl:value-of select="count(../date)" />
> </xsl:template>
>
> produces "3 of 2" and "4 of 2".  Is there a way to restrict position() to
> evaluate the <date> nodes only?  How else could it be done?
>
> I'm new to XSLT, obviously.   Thanks in advance for any help with this.
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list