Subject: [xsl] xsl:with-param From: James Cummings <James.Cummings@xxxxxxxxx> Date: Sun, 15 Jun 2003 20:52:54 +0100 (BST) |
Hi, Am I misunderstanding something or should the follow xslt snippet work: ----- <xsl:template match="/"> <foo> <xsl:apply-templates mode="foo"> <xsl:with-param name="wit">B</xsl:with-param> </xsl:apply-templates> </foo> </xsl:template> <xsl:template match="body" mode="foo"> <xsl:param name="wit" /> <xsl:if test="contains(@wit, $wit)"> <body wit="{$wit}"><xsl:apply-templates mode="foo"/></body> </xsl:if> </xsl:template> ----- I expected that the root template would apply any other templates with mode="foo" and make available to them the param $wit with value 'B'. But the output always has <body wit=""> ... If I supply a default to the xsl:param in the template body, it is of course picked up, but not if I pass it with xsl:with-param. Is it something to do with using @mode with xsl:apply-templates? Or is there something else obvious I'm missing? Thanks for any suggestions, -james -- Dr James Cummings, James.Cummings@xxxxxxxxx, http://www.uea.ac.uk/~q503 Cursus Project, School of Music, University of East Anglia, Norwich, Norfolk, NR4 7TJ, UK Tel:(01603)593-595 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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