Subject: RE: [xsl] How to find all parents having the same child? From: "Michael Kay" <mhk@xxxxxxxxx> Date: Wed, 18 Jun 2003 12:01:08 +0100 |
I suspected as much. It's not two parents having the same child, it's two parents having different children that share the same name. This makes it a classic grouping problem, so go and read the Jeni Tennison tutorial that's been cited twice this morning already. Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Bita Jooooooon > Sent: 18 June 2003 08:50 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] How to find all parents having the same child? > > > Here an example: > > <Quries> > <Query name="query1"> > <Query name="query2"> > <Table name="table1"/> > <Table name="table2"/> > <Query name="query3"> > <Table name="table3"/> > </Query> > </Query> > </Query> > <Query name="query4"> > <Table name="table1"/> > <Table name="table2"/> > <Table name="table3"/> > </Query> > </Queries> > > Given that, I would like to extract all parents for > each leaf like the following: > > table3: query4, query3 > table1: query4, query1 > query3: query2 > query2: query1 > > An example from you on how to get that cross-reference > list would help me a lot. > > regards, > bjoon > > > __________________________________ > Do you Yahoo!? > The New Yahoo! Search - Faster. Easier. Bingo. http://search.yahoo.com > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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