Subject: [xsl] Sorting Alphabetically to an HTML Table From: "Davis, Carrie" <carrie.davis@xxxxxxxxxx> Date: Wed, 18 Jun 2003 10:51:32 -0400 |
Hi. I have been working on this for 3 days and I cannot find the answer, I hope that someone can point me in the right direction: This is the XML: <eip_documents> <doclink> <display_text></display_text> <description> </description> <url></url> </doclink> </eip_documents> The doclinks come in alphabetically to the stylesheet from the XML, so I do not have to sort, but I do have to have the documents in 3 even table columns. So they should look like this if I have 7 documents: Document 1 Document 4 Document 7 Document 2 Document 5 Document 3 Document 6 Or like this if I have 6 documents Document 1 Document 3 Documnet 5 Document 2 Document 4 Document 6 Here is what I have - I have having a hard time starting the new columns: <xsl:template match="doclink" mode="morethanfive"> <td> <table> <xsl:variable name="currentnode" select="position()"/> <xsl:for-each select="."> <tr> <td class="text9pt"> <a> <xsl:attribute name="href">javascript:openUrl ('<xsl:value-of select='url'/>')</xsl:attribute><xsl:value-of select="display_text"/></a><br/><xsl:value-of select="description"/> </td> </tr> <xsl:if test="($currentnode mod $divDoc=0)"> </xsl:if> <xsl:if test="($currentnode mod 3=1)"> </xsl:if> <xsl:if test="($currentnode mod 3=2)"> </xsl:if> </xsl:for-each> </table> </td> </xsl:template> I am sorry if this is trivial. Thank you for any help you can give. Carrie Davis XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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