Subject: Re: [xsl] Cannot use result tree fragment From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 18 Jun 2003 17:36:51 +0100 |
This is a FAQ If you use xsl:variable with content it generates a result tree fragment, you can not query into that, all you can do is copy it with copy-of to the result, or use it as a string. Most XSLT systems have a node-set extension function to generate a node set from a result tree fragment. In your case though your result tree fragment would still not work as it does not have the nodes of the documents only there character data as <xsl:value-of select="document( xsl:value-of _always_ returns a string. You can solve both these pronlems and avoid teh need for a node-set extension function by going <xsl:variable name="vchapmod1" select="document(concat(string($vchapmod/attribute::docref),'.xml'))"/> so now vchapmod1 contains the document nodes directly. You don't need the $vchapmod variable at all that is just the current node so this can be written <xsl:variable name="vchapmod1" select="document(concat(@docref,'.xml'))"/> If you only use this variable in one place you don't need a variable at all and could just have <xsl:for-each select="document(concat(@docref,'.xml')//ht"> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Cannot use result tree fragme, abbouh | Thread | RE: [xsl] Cannot use result tree fr, Michael Kay |
Re: [xsl] expand conditional variab, Wendell Piez | Date | RE: [xsl] xsl:number problem, Wendell Piez |
Month |