Re: [xsl] Fw: omitting empty elements when copying using <xsl:copy-of

[David Carlisle <davidc@xxxxxxxxx>]

> Is there a way i can get the following output (omitting empty elements)
> using xsl:copy-of

Not in general. In general you want to take the "identity transform"
stylesheet from the XSLT spec and one extra template to junk empty
elements

<xsl:template match="*[not(node())]"/>

and you are done.

If you know all your empty elements are at one level and you want to
copy all the non empty children of A then that you can do with a single
copy,

<xsl:copy-of select="*[node()]"/>

David

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