Subject: [xsl] about & ... From: "Fei Zheng" <Fei.Zheng@xxxxxxx> Date: Fri, 20 Jun 2003 09:39:32 -0400 |
I'd like to translate "Food & Drink" into "FoodDrink". I use this: translate('Food & Drink', '&', '' ); Apparently, an error occurs with the code above because of the '&'. Can anyone tell how to handle the '&' here? Thanks in advance. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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