RE: [xsl] No to display the values which are already existing

[Américo Albuquerque <melinor@xxxxxxx>]

Hi

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Dhananjay Pitani
> Sent: Wednesday, June 25, 2003 6:23 PM
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] No to display the values which are already existing
> 
> 
> This is my xml
> 
> <Store>
>   <Title>
>         <Author>Steve</Author>
>         <Name>XSL</Name>
>   </Title>
>   <Title>
>         <Author>Steve</Author>
>         <Name>XML</Name>
>   </Title>
>   <Title>
>         <Author>Dan</Author>
>         <Name>HTML</Name>
>   </Title>
>   <Title>
>         <Author>Dan</Author>
>         <Name>XSL</Name>
>   </Title>
> </Book>
> 
> I want to display the above xml as a html table with two 
> columns Author and 
> Titlle. My task is to display the Author's name only once. 
> The output should 
> be like this
> 
> Author      Title
> 
> Steve        XSL
>                 XML
> Dan           HTML
>                 XSL
> 

You could use a variation of the muenchian method

 <xsl:key match="Title" name="list" use="Author"/>
 <xsl:template match="Store">
  <table>
   <tr>
    <td>Author</td>
    <td>Title</td>
   </tr>
   <!-- instead of applying just to the first element of each group apply to
all -->
   <xsl:apply-templates/>
  </table>
 </xsl:template>
 <xsl:template match="Title">
  <tr>
   <td>
    <!-- display the Author if this is the first element of the group -->
    <xsl:if test="generate-id()=generate-id(key('list',Author))">
     <xsl:apply-templates select="Author"/>
    </xsl:if>
   </td>
   <td>
    <xsl:apply-templates select="Name"/>
   </td>
  </tr>
 </xsl:template>


Hope this helps you. 



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list