Subject: Re: [xsl] how to remove a "wrapper" element? From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Fri, 27 Jun 2003 15:54:51 -0400 |
<xsl:template match="substeps"> <xsl:apply-templates/> </xsl:template>
Cheers, Wendell
Hi.
My xml (as mentioned is posts of yore) uses the following basic structure:
<process_steps> <step/> <step/> <step/> </process_steps>
To make authoring easier, the powers that be have added a "wrapper" element to the dtd/xml structure as follows:
<process_steps> <step> <substeps> <step/> <step/> </substeps> </step> </process_steps>
I've been using a stylesheet (built from much input from this list, especially Americo), that serves everything up in a very nice table, numbered outline, indented, etc.
QUESTION: How would I apply a template to remove the <substeps> element BEFORE the <steps> are used in the table structure so that it doesn't throw everything off?
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] how to remove a "wrapper", Michael Kay | Thread | [xsl] Re: XML Merge, David Carver |
RE: [xsl] XSLT model not "natural"?, Robert Koberg | Date | Re: [xsl] [xslt] Problem changing a, Wendell Piez |
Month |