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Subject: [xsl] how to test for the element type of the current node From: Godmar Back <gback@xxxxxxxxxxxx> Date: Wed, 2 Jul 2003 00:51:20 -0700 (PDT) |
Hi,
what expression do I use if I need to test the type of the current node
in a for-each loop?
Say I have a DTD that has
<!ELEMENT A (B|C)*>
and I want to write
<xsl:template match="A">
<xsl:for-each select="*">
<xsl:choose>
<xsl:when test="if this node is a B"> <--- this is what I can't figure out
apply-templates for B
...
<xsl:otherwise>
do something else for C
...
I tried ".=B" inside the test, which doesn't work, I tried just "B",
I tried "boolean(B)", nothing works.
Note that I believe that using <xsl:template match="B"> won't solve my problem
because I need to do something specific that I only need to if the
B element is nested inside the A element.
This seems such an elementary thing to do (!?), but maybe I still don't
understand XSL well enough to see an alternative.
Thanks!
- Godmar
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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