Subject: Re: [xsl] as efficient as possible... From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Wed, 02 Jul 2003 14:12:24 -0400 |
I am trying to get a list of the products that are listed in the <products> node that are also in the <commission/product> node
Cheers, Wendell
XML --- <earners> <earner> <id /> <name /> </earner> </earners> <clients> <client> <id> <name> <commissions> <commission> <id /> <earnerId /> <product> <productId /> <rate /> </prodcut> </commission> </commissions> <products> <product> <id /> <name /> </product> </products> </client> </clients>
XSL ---
./products/product[id=../../commissions/commission[earnerId=$earnerId]/produ ct/productId]
Problem ------- I am trying to get a list of the products that are listed in the <products> node that are also in the <commission/product> node... The way I have above works.. but it seems to be very slow... I am working with a large amount of data... but I was curious if there was a better way? $earnerId would be the current earner I am trying to calculate totals for... Thanks very much for any help!!
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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