[xsl] "Simple" copy all and find and replace

Subject: [xsl] "Simple" copy all and find and replace
From: "Kai heiko Lienemann" <Xenum81@xxxxxx>
Date: Tue, 8 Jul 2003 12:51:02 +0200
For my program I need XML-Files, where nodes like PHOTO, IMG, FOTO, BILD, BILDCHEN should be renamed with the name IMAGE and the original name should be saved as an attribute "oldname".
The rest of the file should be the same. Just copy all and when the special nodes were found, rename them. I thought it would be really simple, but I tried some hours and had no good result. Maybe sombeody could help me.

Example for the original file:

<?xml version="1.0" encoding="UTF-8"?>

<Class>
   <Images>
       <IMG name="test1" url="/vol/bilder/test1.jpg"/>
       <FOTO name="test2" url="/vol/bilder/tes2t.jpg"/>
       <BILD name="tes3t" url="/vol/bilder/test3.jpg"/>
       <BILDCHEN name="test4" url="/vol/bilder/test4.jpg"/>
       <PHOTO name="test5" url="/vol/bilder/test5.jpg"/>
       <IMAGE name="test6" url="/vol/bilder/test6.jpg"/>
    </Images>
</Class>


should be converted to

<?xml version="1.0" encoding="UTF-8"?>

<Class>
   <Images>
       <IMAGE name="test1" url="/vol/bilder/test1.jpg"/>
       <IMAGE name="test2" url="/vol/bilder/tes2t.jpg"/>
       <IMAGE name="tes3t" url="/vol/bilder/test3.jpg"/>
       <IMAGE name="test4" url="/vol/bilder/test4.jpg"/>
       <IMAGE name="test5" url="/vol/bilder/test5.jpg"/>
       <IMAGE name="test6" url="/vol/bilder/test6.jpg"/>
    </Images>
</Class>



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