Subject: Re: [xsl] template match on attribute, copy but change value From: "Benjamin Farrow" <lovinjess@xxxxxxxxxxx> Date: Thu, 10 Jul 2003 16:03:58 -0700 |
<xsl:template match="@myAtt"> <xsl:attribute name="myAtt"> <xsl:value-of select="'hi there'"/> </xsl:attribute> </xsl:template>
Thanks, Benjamin
From: "Benjamin Farrow" <lovinjess@xxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] template match on attribute, copy but change value Date: Thu, 10 Jul 2003 15:51:08 -0700
Hi,
I'm attempting to find a single attribute and change it's value. I thought this should be simple, but it just doesn't seem to be working. Looking at the Rec it says that xsl:copy is not allowed to copy the attribute and change it's value (what it looks like in the archives that I found as well). So my question is, can I use the identity transform, then have a template matching a specific attribute and copy the attribute to the result, but change it's value?
XML File: <test> <Element myAtt="test"> <child/> </Element> </test>
XSL File:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/"> <xsl:apply-templates select="*"/> </xsl:template>
<xsl:template match="@myAtt">
<xsl:copy> <!-- this is ignored and will not let me change the value -->
<xsl:value-of select="'hi there'"/>
</xsl:copy>
</xsl:template>
<xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template>
</xsl:stylesheet>
Expected Output: <test> <Element myAtt="hi there"> <child/> </Element> </test>
Thanks for any comments, Benjamin
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