RE: [xsl] String literal error

Subject: RE: [xsl] String literal error
From: Américo Albuquerque <melinor@xxxxxxx>
Date: Tue, 29 Jul 2003 17:03:28 +0100
Hi.

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Arthur Maloney
> Sent: Tuesday, July 29, 2003 10:00 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] String literal error
> 
> 
> Hello xsl-list,
> 
> <xsl:param name="delimiter"     select=" ',' "/>
> <xsl:param name="quote-mark" select=" '  "/>
> 
> I am using above to produce SQL csv text file
> Top one works fine
> 
> The 2nd gives error "a string literal was not enclosed"
> Dear xsl-ers ,
> 
> <xsl:param name="delimiter"     select=" ',' "/>
> <xsl:param name="quote-mark" select=" '  "/>
> 
> I'm using the above to produce SQL csv text file.
> 
> 1st works fine
> 2nd gives error "a string literal was not enclosed"

Use <xsl:param name="quote-mark" select=" '&_quot;'  "/> without the '_'


> 
> I'm using <xsl:text>'</xsl:text> as a work around.
> 
> 
> How do you put ' or " into a parameter ?
> 
> 
> -- 
> Best regards,
>  Arthur                          mailto:ArthurMaloney@xxxxxxxxxx
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 



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