Re: [xsl] xsl sort query

Subject: Re: [xsl] xsl sort query
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Fri, 29 Aug 2003 12:10:24 -0400
At 2003-08-29 16:00 +0100, Cormac Fiddes wrote:
I have the following stylesheet & xml data and I need to dynamically sort the
data coming from the xml file.
...
 <GROUP_MEMBER_DETAILS>
         <CFNumber>18888</CFNumber>
         <CFTitle>Mr</CFTitle>
         <CFFirstName>Cormac</CFFirstName>
         <CFSurname>GGGGGG</CFSurname>
         <CFIden>XX999</CFIden>
         <CFCentre>1122</CFCentre>
         <CFProd>Plan B</CFProd>
         <CFCov>Hsteps</CFCov>
         <CFAdu>6</CFAdu>
         <Students>5</Students>
         <Children>7</Children>
         <Status>A</Status>
      </GROUP_MEMBER_DETAILS>
...
<!--
Define sorting in details
-->
<xsl:template match="CF_DETAILS">
...
     <xsl:if test="$CFOption=1">
                <xsl:apply-templates>
                        <xsl:sort select="CFNumber" order="ascending"
data-type="number"/>

For the above fragment to work, CFNumber has to be a child element of a child element of CF_DETAILS, but you don't show enough of your data to know if this is true or not.


Are you, perhaps, just missing a few steps in your XPath address? I don't think you've given enough information, such as describing what you do see that isn't correct, in order for people to comment.

I hope this helps.

............... Ken


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