Re: [xsl] [Fwd: Re: Re: Using a variable in XSLT]

[Tim Müller-Seydlitz <tms@xxxxxxxxxxxxxxxxxx>]

Feedback the way I did
Thanks for the insight I modified  the proposed solution a little bit 
and got the result I expected

<!-- This is to select docomentation in the selected. All documentation 
elements but those in the selected language are not in the result set.
This choose a system.
Only the selected sys is present in the output.
-->

<xsl:template match="xs:documentation">
   <xsl:if test="*[lang('de')]" >
       <xsl:element name="xs:documentation">
           <xsl:copy-of select="@*"/>
           <xsl:apply-templates select="*[name()=$SystemSelected]/text()"/>
       </xsl:element>
   </xsl:if>
</xsl:template>

If I generate the xs:documentation elements directly  with 
<xs:documentation> I get an empty namespace argument in the output like 
<xs:documentation xmlns="">
I don't know whether this is a bug in XML Spy or related to the 
namespaces I used in the header of the XSLT

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:sys="http://www.you-know-who.com/2003/systems";
version="1.0">

Regards
Tim



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