Subject: [xsl] nodeset comparison From: "Todd Kleine" <tkleine@xxxxxxxxxxxxx> Date: Thu, 25 Sep 2003 09:12:08 -0400 |
I am trying to solve the following problem and am having difficulty because I'm new to this. Can anyone help? If I have a nodeset (#1) <menu> <item> <text>test</text> <param required='y'>contactid</param> <param>searchtype</param> </item> </menu> and another nodeset (#2) <parameters> <searchtype>Boolean</searchtype> <anotherparam>testing</anotherparam> </parameters> how do I compare these two such that the test in an <xsl:choose> <xsl:when test=""> ... returns false because the required param contactid (from <param required='y'>contactid</param> in nodeset #1) is not an element name within nodeset #2? If on the other hand the "required" attribute did not exist then the result of the comparison would be true as a match for searchtype as an element name was found. Thanks in advance. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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