[xsl] XPath predicate test and parameter problem

Subject: [xsl] XPath predicate test and parameter problem
From: cknell@xxxxxxxxxx
Date: Tue, 30 Sep 2003 12:42:25 -0400
This is making me crazy. I can't figure out where I'm failing.

Given this data document:
<?xml version="1.0" encoding="UTF-8" ?>
<rowset>
 <row>
  <city>Des Moines</city>
  <state>IA</state>
 </row>
 <row>
  <city>Pittsburgh</city>
  <state>PA</state>
 </row>
 <row>
  <city>Milwaukee</city>
  <state>WI</state>
 </row>
</rowset>

Why does this stylesheet produce the output "Milwaukee",
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="xml" indent="yes" encoding="UTF-8" />

 <xsl:template match="/">
  <xsl:apply-templates select="rowset">
   <xsl:with-param name="st" select="'WI'" />
  </xsl:apply-templates>
 </xsl:template>

 <xsl:template match="rowset">
  <xsl:param name="st" />
  <xsl:value-of select="row[state='WI']/city" />
 </xsl:template>

</xsl:stylesheet>

and this one, only '<?xml version="1.0" encoding="UTF-8" ?>',

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="xml" indent="yes" encoding="UTF-8" />

 <xsl:template match="/">
  <xsl:apply-templates select="rowset">
   <xsl:with-param name="st" select="'WI'" />
  </xsl:apply-templates>
 </xsl:template>

 <xsl:template match="rowset">
  <xsl:param name="st" />
  <xsl:value-of select="row[state='$st']/city" />
 </xsl:template>

</xsl:stylesheet>

To save you the trouble of minutely examining the two, the difference is that in the one that doesn't work the way I think it should, I use the value of the parameter to test the content of the "state" element, where in the one that produces the output I want, I use the literal string 'WI'.

Thanks.


-- 
Charles Knell
cknell@xxxxxxxxxx - email

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