Subject: [xsl] Re: XPath predicate test and parameter problem From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Tue, 30 Sep 2003 19:20:41 +0200 |
> Why does this stylesheet produce the output "Milwaukee", > <?xml version="1.0" encoding="UTF-8" ?> > <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" indent="yes" encoding="UTF-8" /> > > <xsl:template match="/"> > <xsl:apply-templates select="rowset"> > <xsl:with-param name="st" select="'WI'" /> > </xsl:apply-templates> > </xsl:template> > > <xsl:template match="rowset"> > <xsl:param name="st" /> > <xsl:value-of select="row[state='WI']/city" /> > </xsl:template> > > </xsl:stylesheet> > > and this one, only '<?xml version="1.0" encoding="UTF-8" ?>', > > <?xml version="1.0" encoding="UTF-8" ?> > <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" indent="yes" encoding="UTF-8" /> > > <xsl:template match="/"> > <xsl:apply-templates select="rowset"> > <xsl:with-param name="st" select="'WI'" /> > </xsl:apply-templates> > </xsl:template> > > <xsl:template match="rowset"> > <xsl:param name="st" /> > <xsl:value-of select="row[state='$st']/city" /> > </xsl:template> > > </xsl:stylesheet> > > To save you the trouble of minutely examining the two, the difference is that in the one that doesn't work the way I think it should, I use the > value of the parameter to test the content of the "state" element, where in the one that produces the output I want, I use the literal string > 'WI'. No, in the second template you are comparing state to the string '$st': > <xsl:value-of select="row[state='$st']/city" /> and there is no "state" element in your source.xml with string value "$st". Must be: <xsl:value-of select="row[state=$st]/city" /> ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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