Subject: Re: [xsl] Copying XML file over using XSLT From: Mukul Gandhi <mukulgw3@xxxxxxxxx> Date: Mon, 13 Oct 2003 23:47:43 -0700 (PDT) |
sorry I posted a slightly wrong XSL.. The correct one is -- <xsl:template match="/"> <xsl:copy-of select="." /> </xsl:template> The previous one is also working, but this -- is better.. Regards, Mukul --- Mukul Gandhi <mukulgw3@xxxxxxxxx> wrote: > Hi Navid, > Below is the XSL.. > > This is an identity transform -- > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" version="1.0" > encoding="UTF-8" indent="yes"/> > > <xsl:template match="/"> > <xsl:copy-of select="node() | @*" /> > </xsl:template> > > </xsl:stylesheet> > > Regards, > Mukul > > --- "Navid M." <navid89@xxxxxxxxx> wrote: > > Hello, > > > > Is there a short cut for copying all the content > of > > my > > XML file to an XHTML file using XSLT? > > > > i.e. I want to create an XSLT file that will take > > the > > content of an XML file and put it in another file > > exactly as it appears. > > > > Any help would be greatly appreciated. > > > > Thanks, > > Navid M. > > > > __________________________________ > > Do you Yahoo!? > > The New Yahoo! Shopping - with improved product > > search > > http://shopping.yahoo.com > > > > XSL-List info and archive: > > http://www.mulberrytech.com/xsl/xsl-list > > > > > __________________________________ > Do you Yahoo!? > The New Yahoo! Shopping - with improved product > search > http://shopping.yahoo.com > > XSL-List info and archive: > http://www.mulberrytech.com/xsl/xsl-list > __________________________________ Do you Yahoo!? The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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