RE: [xsl] document() function - unknown protocol

Subject: RE: [xsl] document() function - unknown protocol
From: "Robert Koberg" <rob@xxxxxxxxxx>
Date: Tue, 14 Oct 2003 10:41:39 -0700
Hi,

You need to set up a custom javax.xml.transform.URIResolver (assuming you
are using java). You will be passed two arguments when the resolve method is
automatically called when you use document(href [, base]). The first one is
the string you can use to resolve your custom URI.

Best,
-Rob


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-
> list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Jim Nachlin
> Sent: Tuesday, October 14, 2003 10:22 AM
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> 
> Hi List,
> 
> I hope that this is an appropriate question for this list.
> 
> In trying to process an RDF foaf document [1] using the
> stylesheet [2], the processor, which is members of the
> javax.xml.transform package, gives an error which tells me that
> the protocol "arg" is unknown in this statement:
> 
> <xsl:when test="document('arg:/ifp')/*/*/*">
>   <xsl:variable name="ifp">
>     <xsl:copy-of select="document('arg:/ifp')/*[1]/*[1]/*[1]"/>
>   </xsl:variable>
>   <xsl:apply-templates mode="output"  ...   />
> </xsl:when>
> 
> or
> 
> <xsl:variable name="def"
> 
> select="document('arg:/schema')/ns/schema[@ns=$ns]/rdf:RDF/*[@rdf:about=$t
> his or @rdf:ID=$name or @ID=$name]"/>
> 
> and in several other places.
> 
> In looking over the documentation on document(), there is no
> mention of a protocol "arg" or what this could possibly be.  It
> seems that the stylesheet is trying to refer to one of the
> namespace URIs.
> 
> Refs:
> [1] http://www.nachlin.com/foaf.rdf
> [2] http://xml.mfd-consult.dk/foaf/explorer/explorer.xsl
> 
> Thanks in advance for helping an XSL noob.
> 
> Jim
> 
> 
> 
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