[xsl] XPath and recursion

Subject: [xsl] XPath and recursion
From: "Jonny Pony" <jonnypony666@xxxxxxxxxxx>
Date: Thu, 23 Oct 2003 06:31:43 +0000
Hi,

I'm pretty new to XPath and I want to achive the following.

I've got an xml-file, something like this:

<?xml version="1.0" encoding="UTF-8"?>
<document>
	<node value1="DB Objects">
		<node value1="Andreas">
			<node value1="Peter">
				<node value1="Kempten"/>
				<node value1="Ulperting"/>
			</node>
			<node value1="Muahhh"/>
			<node value1="Christoph">
				<node value1="Ulperting"/>
				<node value1="FrankyBoy">
					<node value1="Munich"/>
				</node>
			</node>
		</node>
		<node value1="Christoph">
			<node value1="Munich"/>
			<node value1="FrankyBoy">
				<node value1="Kempten"/>
			</node>
		</node>
		<node value1="Frank"/>
	</node>
	<node value1="Tables">
		<node value1="Andreas">
			<node value1="Peter">
				<node value1="Munich"/>
				<node value1="Ulperting"/>
			</node>
		</node>
		...
	</node>
</document>

And I want to get an output like this after the xsl transformation:

aux1 = insFld(foldersTree, gFld("DB-Objects"))
   aux2 = insFld(aux1, gFld("Andreas",))
		aux3 = insFld(aux2, gFld("Peter"))
			aux4 = insFld(aux3, gFld("Kempten"))
			aux4 = insFld(aux3, gFld("Ulperting"))
 		aux3 = insFld(aux2, gFld("Muahhh"))
		aux3 = insFld(aux2, gFld("Christoph"))
			aux4 = insFld(aux3, gFld("FrankyBoy"))
				aux5 = insFld(aux4, gFld("Munich"))
	 			aux5 = insFld(aux4, gFld("FrankyBoy"))
					aux6 = insFld(aux5, gFld("Kempten"))
					aux6 = insFld(aux5, gFld("Kempten"))
	aux2 = insFld(aux1, gFld("Christoph"))
	aux2 = insFld(aux1, gFld("Frank"))
			aux3 = insFld(aux2, gFld("Peter"))
			aux4 = insFld(aux3, gFld("Ulperting"))
 		aux3 = insFld(aux2, gFld("Muahhh"))
		aux3 = insFld(aux2, gFld("Christoph"))
			aux4 = insFld(aux3, gFld("Ulperting"))
			aux4 = insFld(aux3, gFld("FrankyBoy"))
				aux5 = insFld(aux4, gFld("Munich"))
aux1 = insFld(foldersTree, gFld("Tables"))
   aux2 = insFld(aux1, gFld("Andreas",))
		aux3 = insFld(aux2, gFld("Peter"))
			aux4 = insFld(aux3, gFld("Kempten"))
		aux3 = insFld(aux2, gFld("Christoph"))
			aux4 = insFld(aux3, gFld("Munich"))
			aux4 = insFld(aux3, gFld("Ulperting"))

The idea behind that:
if /document has at least a child, write:
aux1 = insFld(foldersTreeview, gFld( "<xsl:value-of select="@value1"/>"));
if the child got at least another child,write:
aux2 = insFld(aux1, gFld("<xsl:value-of select="@value1"/>");
if the child of the child got at least another child,write:
aux3 = insFld(aux2, gFld("<xsl:value-of select="@value1"/>");
and so on....


I tried to solve this problem for a long time now, but falways failed. Also the numbering of "aux", the deeper i get into the node-tree, is impossibly for me. Have no clue how I would do that.


Thanks Jonny

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