[xsl] Displaying 10 Records at a time - Once Again

["karthikeyan.balasubramanian" <karthikeyan.balasubramanian@xxxxxxxxxxxxx>]

Hi,

  I have found below code bit easier to implement, but
I have one more requirement.

How do I show the below output :

==============================================
heading: 1st record of this 10(1)  |   heading  1st record of this 10(11)

10 records here(1-10)                |   10 records here (11-20)
==============================================
heading: 1st record of this 10(21)|   heading  1st record of this 10(31)

10 records here(21-30)              |   10 records here (31-40)
==============================================

Any help would be of great help.

Have a great day.

Karthikeyan B


XSL Code
=========

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";>
 <xsl:template match="NI">
  <table>
   <xsl:for-each select="TABLE/TBODY/ROW">
    <tr>
     <td>
      <xsl:value-of select="ENTRY[1]/PARA[1]"/>
     </td>
     <td>
      <xsl:value-of select="ENTRY[2]/PARA[2]"/>
     </td>
    </tr>
    <xsl:if test="position() mod 10 = 0">
     <tr>
      <td colspan="2">
       <hr/>
      </td>
     </tr>
    </xsl:if>
   </xsl:for-each>
  </table>
 </xsl:template>
</xsl:stylesheet>

XML Code
=========
<NI PUBLISH="DEC31">
 <TABLE>
  <TBODY>
   <ROW>
    <ENTRY>
     <PARA>MS9557-09</PARA>
     <PARA LEVEL="2">73 34 15  01  010</PARA>
    </ENTRY>
    <ENTRY>
     <PARA/>
     <PARA>3</PARA>
    </ENTRY>
   </ROW>
   <ROW>
    <ENTRY>
     <PARA>MS9557-09</PARA>
     <PARA LEVEL="2">73 34 15  01  010</PARA>
    </ENTRY>
    <ENTRY>
     <PARA/>
     <PARA>3</PARA>
    </ENTRY>
   </ROW>
  </TBODY>
 </TABLE>
</NI>






 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list