Subject: [xsl] Re: Re: Can not convert #STRING to a NodeList! Error.. From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Sat, 8 Nov 2003 20:53:49 +0100 |
> I'm surprised at this explanation. XSLT 1.0 has no notion of the static > or compile-time type of a variable, all typing is done dynamically at > run-time. Declaring a default value for this parameter should make no > difference to anything unless the template is called without a > parameter. > > The code we were shown looks perfectly OK to me. Sorry, you're right. I vaguely remember getting such kind of error for an xsl:param without a default value that shows it's a node-set. This must have been long ago with very old versions of the XSLT processors I use. The code seems OK, maybe the OP is using exactly some old version of an XSLT processor that behaved in this way? ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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