Subject: Re: [xsl] Re: Can not convert #STRING to a NodeList! Error.. From: "arun prasath" <arunwaits@xxxxxxxxxxx> Date: Sun, 09 Nov 2003 20:02:23 +0530 |
please correct me where I have gone wrong. regards s.arun prasath
"arun prasath" <arunwaits@xxxxxxxxxxx> wrote in message
news:BAY2-F124pwACkWHZqY00003637@xxxxxxxxxxxxxx
> Hi,
> In my XSL,
> from the parent template I load a XML file using document() function. and
I
> pass this as parameter to child templates.
> <xsl:call-template name="main">
> <xsl:with-param name="labelsfile" select="document('English.xml')"/>
> </xsl:call-template>
>
> In my child templates, I am retrieving using
> <xsl:param name="labelsfile"/>
>
> I also have declared a key(xsl:key) in the importing xml file in my xsl.
> <xsl:for-each select="$labelsfile">
> <xsl:value-of select="key('label','ecollab.businessfollowedby')"
/>
> </xsl:for-each>
>
> when I transform this using my java program, I get the following
exception.
> Can not convert #STRING to a NodeList!
>
> I want to know why we get this error usually.
> please help
> regards
> s.arun prasath
>
> _________________________________________________________________
> Make fun prints Click here to order. http://www.kodakexpress.co.in
Delivery
> anywhere in India.
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Re: Can not convert #STRING t, Dimitre Novatchev | Thread | [xsl] Re: Re: Can not convert #STRI, Dimitre Novatchev |
[xsl] Re: Can not convert #STRING t, Dimitre Novatchev | Date | [xsl] Re: Re: Can not convert #STRI, Dimitre Novatchev |
Month |