[xsl] position() of parent node

["Robert Ogden" <Robert.Ogden@xxxxxxxx>]

This should be an easy one, but it is eluding me.

XML:
<manual>
	<chapter>
		<textLink>para one</textLink>
		<textLink>para two</textLink>
		<imageLink>image one</imageLink>
		<imageLink>image two</imageLink>
	</chapter>
</manual>

XSLT:
<xsl:for-each select="chapter">
		<xsl:for-each select="textLink">
			//do some stuff
		</xsl:for-each>
		<xsl:for-each select="imageLink">
			<xsl:if test="chapter[position() != 21]">
				//do your thing
			</xsl:if>
		</xsl:for-each>
	</xsl:for-each>

What I am getting at, is that I want to output all text links (easy
enough), and all images for chapters unless the chapter is 21 (which
happens also to be last, which I tried <xsl:if test="chapter[position()
!= last()]">)

Position has given me troubles in the past.

Robert Ogden
IETM Developer
Navy Programs
(763) 572-7121

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