Re: [xsl] Re: Re: Sorting and Merge ---

Subject: Re: [xsl] Re: Re: Sorting and Merge ---
From: Dongling Ding <dling61@xxxxxxxxx>
Date: Tue, 18 Nov 2003 17:49:08 -0800 (PST)
Dimitre, you are a big helper!

Here I have one more problem. Maybe you have a
solution for me.

In the following test code. If I want not only to
search the member name under //results, but also to
check if the name of matched member's parent is same
as the one I passed as prameter.

So, in the test statment, I need to do logic AND for
those two conditions. Can I do that?

If I iterate the result of first critera, and check
the parent of each node, I switch the context to the
//results. Then, I have a problem of copying members
under /doc.

Please help


Dongling



--------------------------------------------------

<xsl:template match="Member[ancestor::doc]">
    <xsl:if test="/*/results/descendant::Member
                            [@name =
current()/@name]">
      <xsl:copy>
        <xsl:copy-of select="@*"/>
        <xsl:apply-templates/>
      </xsl:copy>
    </xsl:if>
  </xsl:template>
</xsl:stylesheet>

When the above transformation is performed on this
source.xml (the 
original
xml document appended with the search results):

<search>
  <doc>
    <MemberList>
      <Member name="P1">
        <Member name="P11">
          <Member name="P111"/>
        </Member>
        <Member name="P12">
          <Member name="P121"/>
        </Member>
      </Member>
      <Member name="P2">
        <Member name="P21"/>
        <Member name="P22"/>
      </Member>
    </MemberList>
  </doc>
  <results>
    <MemberList>
      <Member name="P1">
        <Member name="P12">
          <Member name="P121"/>
        </Member>
      </Member>
      <Member name="P2">
        <Member name="P21"/>
        <Member name="P22"/>
      </Member>
      <Member name="P1">
        <Member name="P11"/>
        <Member name="P12"/>
      </Member>
    </MemberList>
  </results>
</search>




--- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> 
> "Dongling Ding" <dling61@xxxxxxxxx> wrote in message
>
news:20031118183537.2800.qmail@xxxxxxxxxxxxxxxxxxxxxxxxxx
> > Thanks for this new approach. We tried it and it
> is
> > easier than we thought.
> >
> > Dongling
> 
> Glad to help.
> 
> The lesson learned:
> =============
> If you described your problem at the very start as
> you did in your last
> message, you'd have saved two weeks. But instead you
> were asking for some
> details in what you believed must be the solution
> (merging of the results
> and discarding duplicates).
> 
> So, these points are important:
> 
>   1. It is good to start by describing the problem
> which is being solved -- 
> not only the problem within the solution.
> 
>   2. A detailed description and providing a complete
> example is crucial for
> getting help.
> 
>   3. If a solution is too complicated it rarely is
> the best one.
> 
> 
> =====
> Cheers,
> 
> Dimitre Novatchev.
> http://fxsl.sourceforge.net/ -- the home of FXSL
> 
> 
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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