Subject: RE: [xsl] Open file From: "Jim Fuller" <jim.fuller@xxxxxxxxxxxxxx> Date: Mon, 24 Nov 2003 20:17:59 -0000 |
You are asking XSLT 1.0 ( or 2.0 ) to do something it cant do natively, of course you could use the document() function and supply it with random file names, I think you would be best served to either a) supply the transform with an external parameter containing all filenames to search from b) generate an xml file that contains filenames and apply xslt to that, and use the document() command. c) you could place all your xml documents into an xml database, and apply XPATH, XSLT or XQUERY across collections d) use an extension function within xslt ( might have to roll your own ) Generally, it sounds like you want something lightweight like was discussed with transquery, check out the implementation at Chris Bayes site http://www.bayes.co.uk/xml/index.xml?/xml/main.xml click onto transquery from left hand menu, remember you would obviously need MSXML for this approach, but might help inform your approach. gl, jim fuller -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Ricardo Saraiva Sent: Monday, November 24, 2003 10:23 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Hello, I would like know if it is possible to search for a file, and if it doesn't exist, do nothing, else open it. Thanks, Ricardo Saraiva XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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