Re: [xsl] xsl:variable?

[David Carlisle <davidc@xxxxxxxxx>]

> I'm trying to put a node-set in a a variabl
If you use xsl:variable with content rather than select= you get a
result tree fragment not a node set. however that isn't your problem
here.


> <xsl:value-of select="concat($t,...)...

concat is a string function so coerces its argument to a string.
so all your elements have gone at that point.
xsl:value-of also returns the string value, if you want to preserve
structure use copy-of.
So you want
<xsl:copy-of select="$t"/>....
David


-- 
http://www.dcarlisle.demon.co.uk/matthew

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