Subject: RE: [xsl] Line end conversion. From: Jarno.Elovirta@xxxxxxxxx Date: Tue, 2 Dec 2003 16:24:43 +0200 |
FAQ, > I have an odd little problem. I want to match all > linefeeds with a given > element's content, and convert them to "\n". Does anybody > know of a good > way to do so? > > In other words... > > <element>This is a phrase with a line end. > > It's very frustrating.</element> > > ...becomes... > > <element>This is a phrase with a line end.\n\nIt's very > frustrating.</element> Write a recursive template. The FAQ has an entry for this <http://www.dpawson.co.uk/xsl/sect2/replace.html#d6768e55>, but I recommend writing the stylesheet yourself for educational purposes. Cheers, Jarno - Funker Vogt: The International Killer XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Line end conversion., David Carlisle | Thread | RE: [xsl] Line end conversion., Ben Trafford |
Re: [xsl] parent node text() ??, Markus Hanel | Date | Re: [xsl] Line end conversion., Agnes Kielen |
Month |