Subject: Re: [xsl] Re for-each identifying current iteration From: Thomas Rasmussen <tbr77@xxxxxxxxxxxx> Date: Mon, 29 Dec 2003 19:33:19 +0100 |
Hi,Hello
I'm sure there is an incredibly easy way of doing this, but as usual I can't find it!
During a for-each iteration how do you identify what is the integer value of the current iteration.
Thanks
Mark Williams
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
I think position() could do the job: #xsl <xsl:template match="/"> <xsl:for-each select="/root/node"> <xsl:value-of select="position()"/> </xsl:for-each> </xsl:template> # xml-file <root> <node/> <node/> </root>
Regards ThomasRasmussen
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Re: Re for-each identifying c, Dimitre Novatchev | Thread | Re: [xsl] Re for-each identifying c, Skwirel Software Ltd |
[xsl] Re: Re for-each identifying c, Dimitre Novatchev | Date | [xsl] randlist followed by randlist, Norma Yeazell |
Month |