RE: [xsl] Sorting results by output of a conversion template

["Michael Kay" <mhk@xxxxxxxxx>]

> I need to be able to sort my results by the output of this 
> template. So...is there a way using XSL:SORT to call a 
> template (like the one above) and sort the results that way?? 

Not in 1.0.

You can do it using a 2-phase transformation, where the first phase
writes a temporary tree containing the expanded values, and the second
phase sorts the nodes from the temporary tree (accessed using
exslt:node-set()). 

In XSLT 2.0 this becomes easy using a call on an xsl:function from
within the <xsl:sort> select expression.

Michael Kay


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