Subject: RE: [xsl] sorting information from multiple files From: "John Meyer" <jmeyer@xxxxxxxxxxx> Date: Thu, 15 Jan 2004 10:31:36 -0500 |
You can do it (fairly easiliy) if you perform the same operation in each of the for-each elements. Just use a union operator, which is the vertical pipe character '|' and use a single for-each followed by the sort element <xsl:for-each select="document(http:..doc1..)| document(http:..doc2..)| document(http:..doc3..)| document(http:..doc4..)"> <xsl:sort select="my-sort-expression"/> </xsl:for-each> John Meyer Senior Software Engineer Clinician Support Technology 1 Wells Avenue, Suite 201 Newton, MA 02459 www.cstlink.com -----Original Message----- From: james walker [mailto:jameswalkerandy@xxxxxxxxxxx] Sent: Thursday, January 15, 2004 9:56 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] sorting information from multiple files If i have 4 xml files which i am selectively pulling information from, is there anyway i can sort this selective information in ascending order. E.g. i have 4 for-each loops which gather specific info from each file: <xsl:for-each select="document(http:..doc1..)"></xsl:for-each> <xsl:for-each select="document(http:..doc2..)"></xsl:for-each> <xsl:for-each select="document(http:..doc3..)"></xsl:for-each> <xsl:for-each select="document(http:..doc4..)"></xsl:for-each> if the info gathered was letters of the alphabet and doc1 contained "xyz", doc2 contained "abc", doc3 contained "hut" and doc4 contained "jwr", the output using t he foreach loops above would be: x y z a b c h u t j w r however i wanted the result a b c h j r t u w x y z is this possible? _________________________________________________________________ Tired of 56k? Get a FREE BT Broadband connection http://www.msn.co.uk/specials/btbroadband XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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