Re: [xsl] sorting information from multiple files

Subject: Re: [xsl] sorting information from multiple files
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 15 Jan 2004 16:23:03 GMT
document() will accept a node set rather than a string so if it wasn't
for the " " "-" translation you could replace

<xsl:for-each select="child::category">
<xsl:variable name="catnamemod" select="translate(name,' ','_')" />
<xsl:for-each 
select="document($nsindex/*[name()=$catnamemod])/root/child::*">
<xsl:if test="@topfive=true()">

by



<xsl:for-each 
select="document($nsindex/*[name()=current()/category/name])/root/child::*[@topfive]">


Is it not possible to arrange that your nsindex variable has the right names
(by doing the translation at the point you construct that variable?

it's inconvenient to do the translation later as that is a string based
function which stops you using the implicit existential quantification
over a node set that you get with =.

-- 
http://www.dcarlisle.demon.co.uk/matthew

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