RE: RE: [xsl] increment value

[cknell@xxxxxxxxxx]

As has often been said here. You don't (can't) increment a variable. You will have to find another way. Assuming that the root element of your document is named "soup", this will give you the output you asked for.

  <xsl:template match="soup">
    <soup>
    <xsl:apply-templates select="//b" />
    </soup>
  </xsl:template>

  <xsl:template match="b">
    <b>
      <xsl:attribute name="id"><xsl:value-of select="name(.)" /><xsl:value-of select="position()" /></xsl:attribute>
    </b>
  </xsl:template>
-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Ricardo Saraiva <rss@xxxxxxxxxxxxxx>
Sent:     Thu, 22 Jan 2004 17:46:56 -0000
To:       <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  RE: [xsl] increment value

Hi,

	That was an example. The numbers were not to be added to the
string.
	Imagine the example without the numbers.

How do I increment a variable to add to the string?

Thanks,

Ricardo Saraiva


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Andreas L.
Delmelle
Sent: quinta-feira, 22 de Janeiro de 2004 17:16
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] increment value

> -----Original Message-----
> From: Ricardo Saraiva
> 
> 
<snip />
> 	<a>
> 	      <b>1</b>
>       	<b>2</b>
>       </a>
> 
>       <a>
> 	      <b>3</b>
>       	<b>4</b>
>       </a>
>       
> The output would be:
>       
> 	<b id="b1"/> 
> 	<b id="b2"/> 
> 	<b id="b3"/> 
> 	<b id="b4"/> 
> 	.
>

Something like:

<xsl:template match="a/b">
  <xsl:element name="b">
    <xsl:attribute name="id">
      <xsl:value-of select="concat(name(.),.)" />
    </xsl:attribute>
  </xsl:element>
</xsl:template>

Cheers,

Andreas


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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list