Subject: [xsl] finding unique nodes From: Paul Tremblay <phthenry@xxxxxxxxxxxxx> Date: Fri, 23 Jan 2004 01:03:25 -0500 |
I would like to find just the first element of certain nodes. My XML document looks something like this: <doc> <para name = "Normal" left-indent = "18"> text</para> <para name = "Normal" left-indent = "18"> more text</para> <para name = "any possible name" left-indent = "5"> more text</para> <para name = "any possible name" left-indent = "5"> some more text</para> <border top-border = "1"> <para name = "another name" left-indent = "3"> text</para> </border> <table> <row> <cell><para name = "still another name" left-indent="2"> cell text</cell> </row> </table> </doc> I need my resulting document to look like this: <doc> <table-of-styles> <para-style name = "Normal" left-indent = "18"/> <para-style name = "any possible name" left-indent = "3"> <para-style = "another name" left-indent = "3"/> <para-style name = "still another name" left-indent="2"/> </table-of-style> <!--rest of the document--> </doc> Notice that I have just one para-style elelement for each name--one for "Normal", one for "another name", and one for "still another name", and so on. I need to then create a text string for each of the para-style elements. I cannot duplicate the string. Notice also that the para element can occur in many different places. I know to start with something like this: <xsl:template match = "doc"> <xsl:for-each select = "descendant::para"> <!--here is where I don't know what to do--> </xsl:for-each> <xsl:apply-templates/> </xsl:template> I think I have to use a generate-id function in my xsl:for-each loop? But I've never done this before. Thanks -- ************************ *Paul Tremblay * *phthenry@xxxxxxxxxxxxx* ************************ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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