|
Subject: Re: [xsl] FW: Linear counting problem in nested loop From: Mukul Gandhi <mukulgandhi2003@xxxxxxxxxxx> Date: Sun, 25 Jan 2004 10:29:41 +0000 (GMT) |
Hi Dongzhi,
Please try the following XSL template -
<xsl:template match="/MENU">
<xsl:for-each select=".//*">
<xsl:if test="text()">
<xsl:value-of select="position() div 2"/> for
<xsl:value-of select="text()"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
Regards,
Mukul
--- "Wang, Dongzhi (ACF)" <DWang@xxxxxxxxxxx> wrote:
>
> Hi,
>
> I have the following XML and want to implement such
> that I can have
> a linear counter increment with each iteration of
> the parent for-each
> loop and also the nested for-each loop.
>
> <?xml version="1.0"?>
> <MENU>
> <MenuItems>
> <MenuLabel>Menu 1</MenuLabel>
> <SubMenuItems>
> <SubMenuLabel>Sub Menu 1</SubMenuLabel>
> </SubMenuItems>
> <SubMenuItems>
> <SubMenuLabel>Sub Menu
> 11</SubMenuLabel>
> </SubMenuItems>
> </MenuItems>
> <MenuItems>
> <MenuLabel>Menu 2</MenuLabel>
> <SubMenuItems>
> <SubMenuLabel>Sub Menu 2</SubMenuLabel>
> </SubMenuItems>
> </MenuItems>
> </MENU>
>
> e.g. The counter should return as:
> 1 for Menu 1
> 2 for SubMenu 1
> 3 for SubMenu 11
> 4 for Menu 2
> 5 for SubMenu 2
>
> So far, what I got is the counter breaks when it
> reaches the second
> <MenuItems>, as it doesn't know about the subMenu
> from the first
> MenuItems counts 3 already...
>
> Thanks a lot!
> Dongzhi
>
> XSL-List info and archive:
> http://www.mulberrytech.com/xsl/xsl-list
>
________________________________________________________________________
Yahoo! India Mobile: Download the latest polyphonic ringtones.
Go to http://in.mobile.yahoo.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| [xsl] FW: Linear counting problem i, Wang, Dongzhi (ACF) | Thread | Re: [xsl] FW: Linear counting probl, G. Ken Holman |
| [xsl] Re: Displaying XSLT XML resu, Dimitre Novatchev | Date | Re: [xsl] FW: Linear counting probl, G. Ken Holman |
| Month |